f(x) = 4x+c
Let y = 4x+c
y-c = 4x
y-c/4 = x
Therefore, f^-1(x) = x-c/4
What do I do next?
F(x) = 4x+c and f^-1(x) = mx - 5/4. Find the values of m and c.?
You have done it wrong
f(x) = 4x+c
Let y = 4x+c
y-c = 4x
y-c/4 = x
--------------------------------------...
how is this possible
y-c = 4x
then
x = y/4 - c/4
so,
f^-1(x) = x/4 - c/4-------------%26gt;%26gt;(1)
given that
f(x) = 4x+c
and
f^-1(x) = mx - 5/4---------%26gt;%26gt;(2)
Comparing (1) and (2) we get
m = 1/4 and c = 5
================
Hope this will help u...................
Reply:You know that both
:A: f^-1(x)=x-c/4 [what you derived from f(x)=4x+c]
and
:B: f^-1(x)=mx-5/4 [given]
are true. The only possible solution here is (m,c)=(1,5); substituting m=1 would give
:A: f^-1(x)=x-c/4
:B: f^-1(x)=x-5/4
and substituting c=5 would give
:A: f^-1(x)=x-5/4
:B: f^-1(x)=x-5/4
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